x^3+3sinx+2cosx=2

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Solution for x^3+3sinx+2cosx=2 equation:


Simplifying
x3 + 3sinx + 2cosx = 2

Reorder the terms:
2cosx + 3insx + x3 = 2

Solving
2cosx + 3insx + x3 = 2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3insx' to each side of the equation.
2cosx + 3insx + -3insx + x3 = 2 + -3insx

Combine like terms: 3insx + -3insx = 0
2cosx + 0 + x3 = 2 + -3insx
2cosx + x3 = 2 + -3insx

Add '-1x3' to each side of the equation.
2cosx + x3 + -1x3 = 2 + -3insx + -1x3

Combine like terms: x3 + -1x3 = 0
2cosx + 0 = 2 + -3insx + -1x3
2cosx = 2 + -3insx + -1x3

Divide each side by '2osx'.
c = o-1s-1x-1 + -1.5ino-1 + -0.5o-1s-1x2

Simplifying
c = o-1s-1x-1 + -1.5ino-1 + -0.5o-1s-1x2

Reorder the terms:
c = -1.5ino-1 + o-1s-1x-1 + -0.5o-1s-1x2

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